x^2-98x+97=0

Solution for x^2-98x+97=0 equation:

x^2-98x+97=0

a = 1; b = -98; c = +97;
Δ = b2-4ac
Δ = -982-4·1·97
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-96}{2*1}=\frac{2}{2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+96}{2*1}=\frac{194}{2}
=97
$